TM P90

[AZtechAirsoft_DP]

Awesome, do you know the full price for one gun re-wiring and parts?

[XavierMace]

Actually building a new wiring harness or just replacing the connector?

[AZtechAirsoft_DP]

Well both, I was curious if its worth it to do all the labor or have Gearbox do it.

[XavierMace]

If memory serves it's like $4 for a connector with installation.  Rebuilding the harness would probably run around $40, but they will probably recommend just buying a new harness.

[AZtechAirsoft_DP]

Once again thank you for all of your help. I will give them a call tomorrow and get a quote.

[spazz]

i have yet to see a replacement harness for a p90, especialy for low resistence wireing. if you are in phx and dont want to drive to tempe ill do it for $20 if you got the matterial allready. hell i can do it tonight since ill allready be doing some soldering. hit me up: 602-446-2280.
i got a lot of experience with p90 stuff.
did you ever get the tappet plate problem fixed?

[Dayton]

The fuse part is bs because the tamiya has higher resistance eg higher voltage drop across, leading to less amperage for the motor and fuse.

Your thinking backwards there Icorus.  Ohms law: IxR=V | V/I=R | V/R=I |  (V=volts, R=resistance, I=current/amps)
Lets say his battery is providing 10v for ease of explanation and comprehension.
And his Tamiya plugs are creating a poor connection with 2 ohms of resistance. (a poor connection will usually be less than 2 ohms, but 2 is easier to see the side effects, so we will use that)
And his motor pulls 10 amps normally.


In short, as the tamiya connector reduces voltage from resistance, it causes the motor to pull higher amps due it having lower voltage to work with, which can be enough to blow a fuse simply from the voltage drop across the connectors. If you want a more detailed explanation, send me a PM, and I'll write a separate post about it later today if I get time.

[icorus16666]

The fuse part is bs because the tamiya has higher resistance eg higher voltage drop across, leading to less amperage for the motor and fuse.

Your thinking backwards there Icorus.  Ohms law: IxR=V | V/I=R | V/R=I |  (V=volts, R=resistance, I=current/amps)
Lets say his battery is providing 10v for ease of explanation and comprehension.
And his Tamiya plugs are creating a poor connection with 2 ohms of resistance. (a poor connection will usually be less than 2 ohms, but 2 is easier to see the side effects, so we will use that)
And his motor pulls 10 amps normally.


In short, as the tamiya connector reduces voltage from resistance, it causes the motor to pull higher amps due it having lower voltage to work with, which can be enough to blow a fuse simply from the voltage drop across the connectors. If you want a more detailed explanation, send me a PM, and I'll write a separate post about it later today if I get time.

Naw i was probably stoned when i posted, either way f*ck fuses and tamiya connectors. If you can't tell your gun is running right and you need a fuse as an indicator you probably shouldn't be working on a gun. But if you have a constant V. And you have a series circuit with a higher R total due to the poor connector. The amperage, which is the same through out the circuit, would be less than a circuit with a lower R. Provided the V was the same for both circuits.